![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_2.jpg\")
<\/p>\nBir \u00e7at\u0131 in\u015fa ederken veya tadilat yaparken do\u011fru a\u00e7\u0131 se\u00e7imi hem pratiklik hem de estetik a\u00e7\u0131s\u0131ndan \u00e7ok \u00f6nemlidir. \u0130ster profesyonel bir \u00e7at\u0131 ustas\u0131 olun ister kendin yap projesi d\u00fczenleyen bir ev sahibi, tek e\u011fimli bir \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini ve e\u011fim a\u00e7\u0131s\u0131n\u0131 nas\u0131l hesaplayaca\u011f\u0131n\u0131z\u0131 bilmek \u00e7ok \u00f6nemlidir.<\/p>\n
\u00c7at\u0131 e\u011fiminin ne kadar dik olaca\u011f\u0131, \u00e7at\u0131 e\u011fimi olarak da bilinen e\u011fim a\u00e7\u0131s\u0131 ile belirlenir. \u00c7at\u0131n\u0131n su tutma ve \u00e7e\u015fitli hava ko\u015fullar\u0131na dayanma kapasitesini etkiledi\u011fi i\u00e7in bu \u00f6l\u00e7\u00fcm \u00e7ok \u00f6nemlidir. \u00d6rne\u011fin, daha dik bir e\u011fim ya\u011fmur ve kar\u0131 daha etkili bir \u015fekilde tutar, ancak ayn\u0131 zamanda daha fazla malzeme ve yap\u0131sal deste\u011fe ihtiya\u00e7 duyabilir.<\/p>\n
E\u011fim a\u00e7\u0131s\u0131n\u0131n do\u011fru bir \u015fekilde hesaplanmas\u0131 i\u00e7in \u00e7at\u0131n\u0131n y\u00fckselmesi (y\u00fckseklik) ve akmas\u0131 (yatay mesafe) hakk\u0131nda bilgi sahibi olunmas\u0131 gerekir. \u00c7al\u0131\u015fma, \u00e7at\u0131n\u0131n bir ucundan di\u011fer ucuna kadar olan yatay \u00f6l\u00e7\u00fcmd\u00fcr ve y\u00fckselme, \u00e7at\u0131n\u0131n tepesinden taban\u0131na kadar olan dikey mesafedir. A\u00e7\u0131 = arctan(y\u00fckselme\/\u00e7al\u0131\u015fma) bi\u00e7imini alan arctangent fonksiyonu, basit trigonometri kullanarak a\u00e7\u0131y\u0131 hesaplamak i\u00e7in kullan\u0131labilir.<\/p>\n
E\u011fim a\u00e7\u0131s\u0131n\u0131 bulduktan sonra, \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini bulmaya devam edebilirsiniz. \u00c7at\u0131n\u0131n a\u00e7\u0131kl\u0131\u011f\u0131 ve e\u011fim a\u00e7\u0131s\u0131, tek e\u011fimli bir \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini veya y\u00fckselmesini belirler. Ayn\u0131 a\u00e7\u0131kl\u0131k i\u00e7in daha fazla y\u00fckseklik, daha y\u00fcksek bir e\u011fimin sonucudur ve bu, i\u00e7 mekan ve genel mimari tasar\u0131m \u00fczerinde bir etkiye sahip olabilir.<\/p>\n
\u00c7at\u0131n\u0131z\u0131n hem estetik a\u00e7\u0131dan g\u00fczel hem de i\u015flevsel olmas\u0131n\u0131 sa\u011flamak i\u00e7in bu hesaplamalar\u0131n do\u011frulu\u011fu \u00e7ok \u00f6nemlidir. Zamanla, uygun olmayan a\u00e7\u0131lar yap\u0131sal sorunlara, daha y\u00fcksek bak\u0131m masraflar\u0131na ve drenaj sorunlar\u0131na neden olabilir. Bu nedenle, \u00e7at\u0131 kaplama projenizin ba\u015flang\u0131c\u0131nda bu \u00f6l\u00e7\u00fcmleri do\u011fru bir \u015fekilde hesaplamak i\u00e7in zaman ay\u0131rmaya de\u011fer.<\/p>\n
\u00d6nce tek boyutlu bir \u00e7at\u0131 \u00fczerindeki y\u00fck\u00fc belirleyin. Genellikle dinamik ve sabit olarak s\u0131n\u0131fland\u0131r\u0131l\u0131rlar. Bunlardan ilki, bacalar, TV eriyikleri ve antenler gibi di\u011fer nesnelerle birlikte \u00e7at\u0131da s\u00fcrekli olarak bulunan \u00e7at\u0131 kaplamas\u0131n\u0131n a\u011f\u0131rl\u0131\u011f\u0131d\u0131r. T.e. Her zaman \u00e7at\u0131da bulunacak t\u00fcm e\u015fyalar.<\/p>\n
Ayr\u0131ca, de\u011fi\u015fkenler olarak da bilinen dinamik y\u00fckler, kar, dolu, insanlar, onar\u0131m malzemeleri ve aletler gibi zaman zaman meydana gelen y\u00fcklerdir. Buna ek olarak, r\u00fczgar\u0131n yelken kabiliyeti basit \u00e7at\u0131lar\u0131 s\u00f6kebilir. Onlara daha yak\u0131ndan bak\u0131n.<\/p>\n
Kar bas\u0131nc\u0131 e\u011fim a\u00e7\u0131s\u0131ndan da etkilenir. \u00d6rne\u011fin, Moskova b\u00f6lgesindeki y\u00fck yakla\u015f\u0131k 130 kg\/metrekare olacakt\u0131r.m. 30\u00b0C \u00e7at\u0131 e\u011fimi ile.<\/p>\n
Ayr\u0131ca, kar 45 dereceden daha so\u011fuk bir \u00e7at\u0131da kalabilir, ancak bu durum \u00e7at\u0131n\u0131n ne kadar sert oldu\u011funa ba\u011fl\u0131d\u0131r. Orta derecede kar ya\u011f\u0131\u015f\u0131 olan Rusya'n\u0131n merkezinde, tek boyutlu bir \u00e7at\u0131 in\u015fa etmek i\u00e7in 35-30 \u00b0 yeterlidir:<\/p>\n
<\/p>\n
Tek parmakl\u0131 bir \u00e7at\u0131n\u0131n kendisi, kar\u0131n ka\u00e7mas\u0131na izin vermek i\u00e7in minimum 15 \u00b0 a\u00e7\u0131ya sahip olmal\u0131d\u0131r. Maksimum s\u0131cakl\u0131k 60\u00b0 oldu\u011fu i\u00e7in \u00e7at\u0131y\u0131 daha so\u011fuk yapman\u0131n bir anlam\u0131 yoktur.<\/p>\n
\u00c7ok e\u011fimli bir \u00e7at\u0131 r\u00fczgarl\u0131 b\u00f6lgelerde kolayca bozulabilir. Bu durumda rampan\u0131n d\u00fczleminin r\u00fczgar y\u00f6n\u00fcne d\u00f6nmesi tercih edilir. Yine ayn\u0131 nedenle, \u00e7ok yumu\u015fak bir \u00e7at\u0131 kurulmamal\u0131d\u0131r.<\/p>\n
Bu de\u011feri, tek tarafl\u0131 bir \u00e7at\u0131 i\u00e7in elveri\u015fsiz sabit ve ge\u00e7ici y\u00fcklerin bir kombinasyonu olarak hesaplad\u0131\u011f\u0131n\u0131zdan emin olun. Kiri\u015f yap\u0131s\u0131n\u0131n dayanabilmesi gereken en \u00f6nemli nokta.<\/p>\n
\u00d6rne\u011fin, \u015fiddetli bir f\u0131rt\u0131na ve kar ya\u011f\u0131\u015f\u0131 s\u0131ras\u0131nda \u00e7at\u0131ya \u00e7\u0131kman\u0131z gerekecek – ama tek ba\u015f\u0131n\u0131za de\u011fil; yard\u0131ma ihtiyac\u0131n\u0131z olacak. Binan\u0131z\u0131n ayn\u0131 anda iki ki\u015fiyi, r\u00fczgar\u0131 ve kar\u0131 ta\u015f\u0131mas\u0131 m\u00fcmk\u00fcn m\u00fc?? \u00d6nceden fark\u0131nda olmak daha iyidir.<\/p>\n
Tek bloklu \u00e7at\u0131n\u0131n e\u011fimi 6\u00b0 ile 60\u00b0 aras\u0131nda de\u011fi\u015fmektedir ki bu olduk\u00e7a geni\u015f bir aral\u0131kt\u0131r. Her \u015fey in\u015fa etmeyi planlad\u0131\u011f\u0131n\u0131z yere ba\u011fl\u0131d\u0131r: \u00e7at\u0131dan d\u00fczenli olarak b\u00fcy\u00fck miktarda kar temizlemeniz gerekiyorsa, daha dik bir e\u011fim olu\u015fturun; kendinizi r\u00fczgardan korumak istiyorsan\u0131z, daha yumu\u015fak bir e\u011fim olu\u015fturun. Ayr\u0131ca, belirli bir k\u00f6m\u00fcre sahip tek e\u011fimli bir \u00e7at\u0131, hava ak\u0131\u015f\u0131n\u0131 do\u011fru y\u00f6ne y\u00f6nlendirerek ya\u011f\u0131\u015f\u0131 yakalar ve uzakla\u015ft\u0131r\u0131r. Bunu akl\u0131n\u0131zda bulundurun!<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_1.jpg\")
<\/p>\n
Su, tek tarafl\u0131 bir \u00e7at\u0131da a\u00e7\u0131 b\u00fcy\u00fcd\u00fck\u00e7e daha h\u0131zl\u0131 hareket eder. \u00c7at\u0131 kaplamas\u0131n\u0131n kendisi \u00e7ok daha uzun s\u00fcre dayanacakt\u0131r \u00e7\u00fcnk\u00fc ne kir ne de yaprak kalacakt\u0131r. Ayr\u0131ca, se\u00e7ilen kiremit veya metal profilin g\u00f6rsel \u00e7ekicili\u011fi b\u00f6yle bir \u00e7at\u0131da daha belirgindir ve bu da ev sahipleri \u00fczerinde genellikle b\u00fcy\u00fck bir etkiye sahiptir.<\/p>\n
D\u00fc\u015f\u00fck akneli yama\u00e7larda, ya\u011f\u0131\u015f ve eriyen su \u00e7ok daha yava\u015f bir h\u0131zda akar, bu da su durgunlu\u011fu, kir birikmesi ve buz s\u0131k\u0131\u015fmas\u0131 olas\u0131l\u0131\u011f\u0131n\u0131 art\u0131r\u0131r. Bu t\u00fcr \u00e7at\u0131larda yosun h\u0131zla b\u00fcy\u00fcr ve ye\u015fillik devam eder. \u00f6zellikle \u00e7at\u0131 kaplamas\u0131 d\u00fcz de\u011filse.<\/p>\n
Su, ya\u011fmur veya kar erimesinden sonra \u00e7at\u0131 kaplama malzemesinin y\u00fczeyinden kolayca yuvarlanabilmelidir. Bu, \u00e7at\u0131 i\u00e7in birincil gerekliliktir. E\u011fim \u00e7ok d\u00fc\u015f\u00fckse nem t\u00fcm kuytu k\u00f6\u015felerde \u00e7ok uzun s\u00fcre kalacakt\u0131r. Ayr\u0131ca, d\u0131\u015far\u0131da ne kadar uzun s\u00fcre kal\u0131rsa, s\u0131zma ve nem, hasarl\u0131 yal\u0131t\u0131m ve metal \u00e7at\u0131 bile\u015feni korozyonu gibi \u00e7e\u015fitli sorunlara neden olma olas\u0131l\u0131\u011f\u0131 da o kadar artar:<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_3.jpg\")
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_4.jpg\")
<\/p>\n
Bununla birlikte, baz\u0131 avantajlar da vard\u0131r: tek e\u011fimli bir \u00e7at\u0131n\u0131n i\u00e7 oda geometrisi, e\u011fim a\u00e7\u0131s\u0131 ne kadar k\u00fc\u00e7\u00fck olursa geleneksel k\u00fcp ile o kadar yak\u0131n hizalan\u0131r. Sonu\u00e7 olarak, daha olumlu kar\u015f\u0131lan\u0131r ve daha etkili bir \u015fekilde kullan\u0131l\u0131r.<\/p>\n
Ancak bu durumda, ne eriyik ne de ya\u011fmur suyunun kiri\u015f sisteminin i\u00e7ine girmemesini sa\u011flamak i\u00e7in su yal\u0131t\u0131m\u0131na \u00e7ok dikkat etmelisiniz. Membranlar, rulo yal\u0131t\u0131m veya t\u00fcm levhalar gibi \u00e7at\u0131 kaplamalar\u0131n\u0131n kullan\u0131lmas\u0131 gerekir.<\/p>\n
Tek oluklu bir \u00e7at\u0131, standart e\u011fim a\u00e7\u0131s\u0131 ile a\u015fa\u011f\u0131daki y\u00f6ntem kullan\u0131larak in\u015fa edilir:<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_5.jpg\")
<\/p>\n
Ters \u00e7at\u0131 s\u0131kl\u0131kla k\u00f6\u015fesi sadece 3-5 \u00b0 veya tamamen d\u00fcz olan tek tarafl\u0131 bir \u00e7at\u0131 ile yap\u0131l\u0131r. Tipik bir \u00e7at\u0131 gibi de\u011fildir, \u00e7\u00fcnk\u00fc turtadaki \u00e7ok katmanl\u0131 i\u00e7 dolgu tamamen farkl\u0131 bir d\u00fczende olu\u015fturulmu\u015ftur. Ayr\u0131ca, \u00e7at\u0131 kaplamas\u0131nda a\u015f\u0131nmaya ve fiziksel zorlanmaya kar\u015f\u0131 y\u00fcksek diren\u00e7li malzemeler kullan\u0131l\u0131r. Verandalar, bah\u00e7eler veya a\u00e7\u0131k alanlar s\u0131kl\u0131kla b\u00f6yle bir \u00e7at\u0131 \u00fczerinde kurulur.<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_6.jpg\")
<\/p>\n
\u0130\u015flevsel olarak, havaland\u0131rmal\u0131, havaland\u0131rmas\u0131z ve birle\u015fik tek tarafl\u0131 \u00e7at\u0131lar \u00fc\u00e7 ana kategoridir. Her se\u00e7ene\u011fe daha yak\u0131ndan bak\u0131n.<\/p>\n
Bunlar kapal\u0131 yap\u0131larda bulunur. Havaland\u0131rma olarak bilinen, yal\u0131t\u0131m katmanlar\u0131 aras\u0131ndaki zay\u0131f ve benzersiz bo\u015fluklardan ge\u00e7en hava, nem damlac\u0131klar\u0131n\u0131 toplar ve yal\u0131t\u0131mdan d\u0131\u015far\u0131 atar.<\/p>\n
Bu t\u00fcr bir havaland\u0131rman\u0131n sa\u011flanmamas\u0131 durumunda, nem yal\u0131t\u0131m\u0131n i\u00e7ine s\u0131zmaya devam edecek (yine de s\u0131zmaktad\u0131r) ve yal\u0131t\u0131m c\u00fcret etmeye, bozulmaya ba\u015flayacakt\u0131r. Sonunda, t\u00fcm \u00e7at\u0131 pastas\u0131 yava\u015f yava\u015f \u00e7\u00f6kecek.<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_7.jpg\")
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_8.jpg\")
<\/p>\n
Avlular ve m\u00fc\u015ftemilatlar bu t\u00fcr d\u00fcz \u00e7at\u0131lar i\u00e7in ba\u015fl\u0131ca yerlerdir. B\u00f6yle bir \u00e7at\u0131n\u0131n a\u00e7\u0131s\u0131nda herhangi bir k\u0131s\u0131tlama yoktur, ancak genellikle sadece 3-6 \u00b0 aras\u0131nda de\u011fi\u015fir.<\/p>\n
Bu t\u00fcr \u00e7at\u0131lar havaland\u0131rma gerektirmez, \u00e7\u00fcnk\u00fc alandaki hava do\u011fal olarak sirk\u00fcle olacak ve duvarlar\u0131 olsun ya da s\u0131k s\u0131k geni\u015f kap\u0131lar a\u00e7\u0131ls\u0131n (garajda oldu\u011fu gibi) sokaktaki su buharlar\u0131n\u0131 ortadan kald\u0131racakt\u0131r. Bu arada, bu t\u00fcr binalarda neredeyse hi\u00e7 olu\u015fmaz:<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_9.jpg\")
<\/p>\n
Tek kiri\u015fli bir \u00e7at\u0131n\u0131n kiri\u015fleri ve \u00e7at\u0131 e\u011fimi tavan\u0131n yatay d\u00fczlemine do\u011fru a\u00e7\u0131l\u0131 oldu\u011funda, bu a\u00e7\u0131 olarak adland\u0131r\u0131l\u0131r. Ayr\u0131ca, \u00e7at\u0131n\u0131za uygun mekanik mukavemeti kazand\u0131rmak istiyorsan\u0131z, bu plan\u0131 dikkatlice de\u011ferlendirin:<\/p>\n
![](\"\/wp-content\/uploads\/2024\/07\/kak-pravilno-rasschitat-ugol-naklona-i-vysotu_10.jpg\")
<\/p>\n
E\u011fim e\u011fimi y\u00fczde olarak ve derece cinsinden ifade edilir. Ancak, dereceler daha da belirgin ise (okul geometri oran\u0131 nedeniyle) ne ilgi var? Paten ve korni\u015f y\u00fckseklik farklar\u0131n\u0131n yatay e\u011fime oran\u0131n\u0131n 100 ile \u00e7arp\u0131m\u0131 ilgilenilen de\u011ferdir.<\/p>\n
Bir ba\u015fka ilgin\u00e7 nokta da, bir\u00e7ok mimar\u0131n tek tarafl\u0131 bir \u00e7at\u0131n\u0131n a\u00e7\u0131s\u0131n\u0131, bahar\u0131n ortas\u0131nda belirli bir yerde g\u00fcne\u015fin y\u00fckselme a\u00e7\u0131s\u0131na uyacak \u015fekilde hassas bir \u015fekilde \u00f6l\u00e7mesidir. B\u00f6ylece g\u00f6lgenin ne zaman ve ne oldu\u011funu tam olarak belirleyebilirsiniz; bu da evlerin \u00f6n\u00fcndeki teraslar\u0131 ve di\u011fer toplanma yerlerini tasarlamak i\u00e7in \u00e7ok \u00f6nemlidir.<\/p>\n
Tek tarafl\u0131 bir \u00e7at\u0131 i\u00e7in, modern \u00e7at\u0131 kaplama malzemeleri minimum ve maksimum e\u011fim a\u00e7\u0131s\u0131na ili\u015fkin \u00f6zelliklere de sahiptir:<\/p>\n
Do\u011fal olarak, oluklu mukavva ve \u00e7at\u0131 malzemesi gibi daha ucuz malzemeler kullanabilirsiniz – a\u00e7\u0131 ne kadar k\u00fc\u00e7\u00fck olursa.<\/p>\n
Tipik olarak en az 30 \u00b0 e\u011fimli oldu\u011funda kullan\u0131lan ayn\u0131 \u00e7at\u0131 kaplama tiplerinin art\u0131k \u00f6zellikle d\u00fc\u015f\u00fck akneli \u00e7at\u0131lar i\u00e7in geli\u015ftirildi\u011fini \u00f6\u011frenmek sizi \u015fa\u015f\u0131rtabilir. Hangi ama\u00e7 i\u00e7in? Bu, bize kadar ula\u015fan Alman tarz\u0131d\u0131r: neredeyse yumu\u015fak olan tek tarafl\u0131 \u015f\u0131k bir \u00e7at\u0131. Ancak, nas\u0131l? Basit\u00e7e s\u00f6ylemek gerekirse, \u00fcreticiler kilitlerin standard\u0131n\u0131 y\u00fckseltir, daha fazla ta\u015fma \u00fcretir ve kir direncini daha dikkatli bir \u015fekilde dikkate al\u0131r. Ba\u015fka numara yok.<\/p>\n
\n Tek e\u011fimli bir \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini ve a\u00e7\u0131s\u0131n\u0131 do\u011fru bir \u015fekilde hesaplamak i\u00e7in temelleri anlamak \u00e7ok \u00f6nemlidir. \u00c7at\u0131n\u0131n drenaj\u0131 ve dayan\u0131kl\u0131l\u0131\u011f\u0131, \u00e7at\u0131n\u0131n ne kadar dik oldu\u011funu belirleyen e\u011fim a\u00e7\u0131s\u0131ndan etkilenir. Bu a\u00e7\u0131y\u0131 bulmak i\u00e7in temel trigonometri kullan\u0131labilir; bu a\u00e7\u0131 genellikle y\u00fckselmenin (y\u00fcksekli\u011fin) ko\u015fu (geni\u015fli\u011fin yar\u0131s\u0131) \u00fczerindeki arktanjant\u0131 olarak ifade edilir. Taban geni\u015fli\u011finin a\u00e7\u0131n\u0131n sin\u00fcs\u00fc ile \u00e7arp\u0131lmas\u0131 \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini verir. Bu hesaplamalar, in\u015faat veya tadilat projeleri i\u00e7in hassas \u00f6l\u00e7\u00fcmleri garanti ederek \u00e7at\u0131n\u0131n i\u015flevselli\u011fini ve bina y\u00f6netmeliklerine uygunlu\u011funu garanti eder.\n <\/p><\/blockquote>\n
Ad\u0131m 6. Kiri\u015f sistemi ile belirliyoruz<\/h2>\n
Ayr\u0131ca, ama\u00e7lanan y\u00fcklere ve \u00e7at\u0131n\u0131n se\u00e7ilen e\u011fim a\u00e7\u0131s\u0131na ba\u011fl\u0131 olarak duvara ba\u011flanacak mertek tipini se\u00e7iyoruz. Dolay\u0131s\u0131yla, bunlar\u0131n \u00fc\u00e7 farkl\u0131 t\u00fcr\u00fc vard\u0131r: lushing, kayar ve as\u0131l\u0131 kiri\u015fler.<\/p>\n
Asma kiri\u015fleri<\/h3>\n
Ba\u011flant\u0131n\u0131n g\u00fc\u00e7l\u00fc olmas\u0131 gerekti\u011finde, as\u0131l\u0131 kiri\u015fler tek se\u00e7enektir; ancak, yan destekler aras\u0131nda as\u0131l\u0131 olan kiri\u015fler i\u00e7in destek sa\u011flaman\u0131n bir yolu yoktur.<\/p>\n
Basit\u00e7e s\u00f6ylemek gerekirse, i\u00e7 b\u00f6lmeler yoktur; sadece d\u0131\u015f destek duvarlar\u0131 mevcuttur. Bu kiri\u015f sisteminin olduk\u00e7a karma\u015f\u0131k oldu\u011funu ve yap\u0131m\u0131nda dikkatli d\u00fc\u015f\u00fcn\u00fclmesi gerekti\u011fini varsayal\u0131m. B\u00fcy\u00fck a\u00e7\u0131kl\u0131klar ve duvarlar \u00fczerindeki bas\u0131n\u00e7 sorunun temelini olu\u015fturmaktad\u0131r:<\/p>\n
<\/p>\n
Alternatif olarak, bu projede oldu\u011fu gibi:<\/p>\n
<\/p>\n
Nammed kiri\u015fler<\/h3>\n
Burada t\u00fcm \u00e7at\u0131 taraf\u0131ndan en az \u00fc\u00e7 deste\u011fe bask\u0131 uygulanmaktad\u0131r: iki d\u0131\u015f duvar ve bir i\u00e7 duvar. Ayr\u0131ca, en az 5×5 cm'lik \u00e7ubuklar ve 5×15 cm'lik mertek ayaklar\u0131ndan olu\u015fan kesitlerinde yo\u011fun mertek kullan\u0131m\u0131 a\u00e7\u0131k\u00e7a g\u00f6r\u00fclmektedir.<\/p>\n
Kayar kiri\u015fler<\/h3>\n
Patendeki bir k\u00fct\u00fck, bu kiri\u015f sistemindeki desteklerden biri olarak i\u015flev g\u00f6r\u00fcr. Ve "slaytlar" gibi benzersiz bile\u015fenler kiri\u015flere ba\u011flamak i\u00e7in kullan\u0131l\u0131r. Bunlar, b\u00fcz\u00fcld\u00fcklerinde \u00e7atlaklar\u0131 \u00f6nlemek i\u00e7in kiri\u015flerin duvarlar\u0131 hafif\u00e7e \u00f6ne do\u011fru hareket ettirmesine yard\u0131mc\u0131 olan metal bile\u015fenlerdir. \u00c7ok az! Ayr\u0131ca \u00e7at\u0131, bu cihaz sayesinde k\u00fct\u00fck evin g\u00f6zle g\u00f6r\u00fcl\u00fcr b\u00fcz\u00fclmesine herhangi bir sorun olmadan dayanabilmektedir.<\/p>\n
Temel fikir \u015fudur: D\u00fc\u011f\u00fcmlerin kiri\u015f sistemi ne kadar \u00e7ok olursa o kadar esnek ve sa\u011flam olur. Tek tarafl\u0131 bir \u00e7at\u0131 k\u0131r\u0131lmadan ne kadar fazla bask\u0131ya dayanabilirse, o kadar fazla kar ve \u00e7at\u0131 a\u011f\u0131rl\u0131\u011f\u0131n\u0131 ta\u015f\u0131yabilir. Bununla birlikte, baz\u0131 kiri\u015f sistemlerinin tipik olarak statik olan ba\u011flant\u0131lar\u0131 vard\u0131r:<\/p>\n
<\/p>\n
\n\n
\n E\u011fim A\u00e7\u0131s\u0131n\u0131n Hesaplanmas\u0131<\/td>\n \u00c7at\u0131n\u0131n y\u00fckseli\u011fini (dikey y\u00fckseklik) ve a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 (yatay mesafe) \u00f6l\u00e7\u00fcn. A\u00e7\u0131y\u0131 derece cinsinden elde etmek i\u00e7in y\u00fckseli\u015fi a\u00e7\u0131kl\u0131\u011fa b\u00f6l\u00fcn ve bu b\u00f6l\u00fcm\u00fcn arktanjant\u0131n\u0131 (tan-\u00b9) bulun.<\/td>\n<\/tr>\n \n \u00c7at\u0131 Y\u00fcksekli\u011finin Hesaplanmas\u0131<\/td>\n Pisagor teoremini kullan\u0131n: a\u00e7\u0131kl\u0131\u011f\u0131n karesini al\u0131n, y\u00fckselmenin karesini al\u0131n, bunlar\u0131 toplay\u0131n ve tabandan \u00e7at\u0131n\u0131n tepesine kadar olan y\u00fcksekli\u011fi bulmak i\u00e7in karek\u00f6k\u00fcn\u00fc al\u0131n.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n Do\u011fru tasar\u0131m ve i\u015fletimi garanti etmek i\u00e7in tek e\u011fimli bir \u00e7at\u0131n\u0131n y\u00fcksekli\u011fi ve e\u011fim a\u00e7\u0131s\u0131 hesaplanmal\u0131d\u0131r. A\u00e7\u0131 olarak da adland\u0131r\u0131lan e\u011fim, \u00e7at\u0131n\u0131n ne kadar dik e\u011fimli oldu\u011funu kontrol eden \u015feydir. Bu a\u00e7\u0131y\u0131 belirlemek i\u00e7in y\u00fckselti (y\u00fckseklik) ve e\u011fimi (\u00e7at\u0131n\u0131n kenar\u0131ndan zirveye kadar olan yatay mesafe) kullanan basit bir trigonometrik form\u00fcl kullan\u0131labilir. Derece cinsinden a\u00e7\u0131, y\u00fckseli\u015fin ko\u015fuya b\u00f6l\u00fcnmesi ve ard\u0131ndan sonucun arktanjant\u0131n\u0131n al\u0131nmas\u0131yla bulunabilir.<\/p>\n
A\u00e7\u0131y\u0131 hesaplad\u0131ktan sonra \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini anlamak kolayd\u0131r. \u00c7at\u0131n\u0131n tepe noktas\u0131 ile taban\u0131 aras\u0131ndaki dikey mesafe y\u00fckseklik olarak adland\u0131r\u0131l\u0131r. E\u011fim a\u00e7\u0131s\u0131n\u0131n bu \u00f6l\u00e7\u00fcm \u00fczerinde do\u011frudan etkisi vard\u0131r; a\u00e7\u0131 ne kadar dik olursa \u00e7at\u0131 o kadar uzun olur. \u00c7at\u0131 yap\u0131s\u0131n\u0131 tasarlamak, gerekli malzemeleri belirlemek ve kar veya ya\u011fmur suyunun uygun \u015fekilde drenaj\u0131n\u0131 sa\u011flamak i\u00e7in y\u00fcksekli\u011fi bilmek \u00e7ok \u00f6nemlidir.<\/p>\n
Yetersiz drenaj veya yap\u0131sal dengesizlik gibi olas\u0131 sorunlar\u0131 \u00f6nlemek i\u00e7in bu hesaplamalar\u0131n do\u011fru olmas\u0131 \u00e7ok \u00f6nemlidir. Bir a\u00e7\u0131n\u0131n \u00f6l\u00e7\u00fcm\u00fcndeki k\u00fc\u00e7\u00fck bir hata daha sonra b\u00fcy\u00fck sorunlara neden olabilir. Bu nedenle, in\u015faata ba\u015flamadan \u00f6nce, hesaplamalar\u0131 iki kez kontrol ederek ve m\u00fcmk\u00fcnse bir profesyonele dan\u0131\u015farak \u00f6l\u00e7\u00fcmlerinizin do\u011frulu\u011funu teyit etmeniz \u00f6nerilir.<\/p>\n
Ayr\u0131ca, bu parametrelerin nas\u0131l hesaplanaca\u011f\u0131n\u0131 bilmek hem in\u015faat\u00e7\u0131lara hem de ev sahiplerine daha fazla g\u00fc\u00e7 sa\u011flar. \u00c7at\u0131 tasar\u0131m\u0131n\u0131n alt\u0131nda yatan mimari kavramlar\u0131n daha derinlemesine anla\u015f\u0131lmas\u0131n\u0131 ve daha iyi planlama ve b\u00fct\u00e7eleme yap\u0131lmas\u0131n\u0131 sa\u011flar. Bu hesaplamalar\u0131n nas\u0131l yap\u0131laca\u011f\u0131n\u0131 bilmek, ister yeni bir ev in\u015fa ediyor olun, ister eski bir \u00e7at\u0131y\u0131 tadilattan ge\u00e7iriyor olun ya da sadece mimarinin teknik detaylar\u0131yla ilgileniyor olun, faydal\u0131 bir beceridir.<\/p>\n","protected":false},"excerpt":{"rendered":"
Bir \u00e7at\u0131 in\u015fa ederken veya tadilat yaparken do\u011fru a\u00e7\u0131 se\u00e7imi hem pratiklik hem de estetik a\u00e7\u0131s\u0131ndan \u00e7ok \u00f6nemlidir. \u0130ster profesyonel bir \u00e7at\u0131 ustas\u0131 olun ister kendin yap projesi d\u00fczenleyen bir ev sahibi, tek e\u011fimli bir \u00e7at\u0131n\u0131n y\u00fcksekli\u011fini ve e\u011fim a\u00e7\u0131s\u0131n\u0131 nas\u0131l hesaplayaca\u011f\u0131n\u0131z\u0131 bilmek \u00e7ok \u00f6nemlidir. \u00c7at\u0131 e\u011fiminin ne kadar dik olaca\u011f\u0131, \u00e7at\u0131 e\u011fimi olarak da […]<\/p>\n","protected":false},"author":68,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[21],"tags":[],"class_list":["post-3202","post","type-post","status-publish","format-standard","","category-roofs"],"yoast_head":"\n
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